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JEE Main 202124 FebruaryMorning Shift
Exam
JEE Main
Year
2021
Date
24 February
Shift
Morning Shift
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2021 · 24 February · Morning Shift · Chemistry · Redox Reactions

The reaction of sulphur in alkaline medium is given below: S _ 8(s)...

The reaction of sulphur in alkaline medium is given below:

S8(s)+aOH(aq)−→bS(aq)2−+cS2O3(aq)2−+dH2O(l){S}_{8\left(s\right)} + a{OH}_{\left(aq\right)}^{-} \to b{S}_{\left(aq\right)}^{2 -} + c{S}_{2}{O}_{3\left(aq\right)}^{2 -} + d{H}_{2}{O}_{\left(l\right)}

The values of 'aa' is______ (Integer answer)

The reaction of sulphur in alkaline medium is given below: S _ 8(s) + a OH _ (aq) ^ - → b S _ (aq) ^ 2 - + c S _ 2 O _

Correct answer

0

Step-by-step solution

The reaction of sulphur in alkaline medium is given below: S _ 8(s) + a OH _ (aq) ^ - → b S _ (aq) ^ 2 - + c S _ 2 O _

For balancing in basic medium add equal number of OH⊖{OH}^{⊖}. That of H+{H}^{+}

2S8+12H2O+24OH⊖⟶8S2−+4S2O82−+24H2O2{S}_{8} + 12{H}_{2}O + 24{OH}^{⊖} ⟶ 8{S}^{2 -} + 4{S}_{2}{O}_{8}^{2 -} + 24{H}_{2}O

2S8+24OH⊖→8S2−+4S2O82−+12H2O2{S}_{8} + 24{OH}^{⊖} \to 8{S}^{2 -} + 4{S}_{2}{O}_{8}^{2 -} + 12{H}_{2}O

S8+12OH⊖→4S2−+2S2O82−+6H2O{S}_{8} + 12{OH}^{⊖} \to 4{S}^{2 -} + 2{S}_{2}{O}_{8}^{2 -} + 6{H}_{2}O

a=12a = 12

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