Consider the following reaction: x MnO _ 4 ^ - + y C _ 2 O _ 4 ^ 2 - + zH ^ + ⟶ x Mn ^ 2 + + 2y CO _ 2 + (z)/(2) H _ 2 O The values of x, y and z in the reaction are, respectively:

Correct answer: A. 2, 5and16 cases C _ 2 O _ 4 ^ 2 - & ⟶ & 2 CO _ 2 + 2 e ^ - ] × 5 MnO _ 4 ^ - + 8 H ^ + + 5 e ^ - & ⟶ & Mn ^ 2 + + 4 H _ 2 O ] × 2 cases ----------------------------------------------------------------------------------- cases 2 MnO _ 4 ^ - + 1 6 H ^ + + 5 C _ 2 O _ 4 ^ 2 - & ⟶ cases 1 0 CO _ 2 + 2 Mn ^ 2 + + 8 H _ 2 O MnO _ 4 ^ - ⇒ x = 2 C _ 2 O _ 4 ^ 2 - ⇒ y = 5 H ^ + ⇒ z = 1 6

JEE Main 20137 April

Exam: JEE Main
Year: 2013
Date: 7 April
Subject: Chemistry
Chapter: Redox Reactions

JEE Main 2013 · 7 April · Chemistry · Redox Reactions

Consider the following reaction: x MnO _ 4 ^ - + y C _ 2 O _ 4 ^ 2...

Consider the following reaction:

x{MnO}_{4}^{-} + y{C}_{2}{O}_{4}^{2 -} + {zH}^{+} ⟶ x{Mn}^{2 +} + 2y{CO}_{2} + \dfrac{z}{2}{H}_{2}O

The values of x, y and z in the reaction are, respectively:

Options

A $2, 5and16$
B $5, 2and8$
C $5, 2and16$
D $2, 5and8$

Correct answer

A. $2, 5and16$

Step-by-step solution

\begin{cases}{\text{C}}_{2} {\text{O}}_{4}^{2 -} & ⟶ & 2 {\text{CO}}_{2} + 2 {\text{e}}^{-} ] \times 5 \\ {\text{MnO}}_{4}^{-} + 8 {\text{H}}^{+} + 5 {\text{e}}^{-} & ⟶ & {\text{Mn}}^{2 +} + 4 {\text{H}}_{2} \text{O} ] \times 2\end{cases}

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\begin{cases}2 {\text{MnO}}_{4}^{-} + 1 6 {\text{H}}^{+} + 5 {\text{C}}_{2} {\text{O}}_{4}^{2 -} & ⟶\end{cases} 1 0 {\text{CO}}_{2} + 2 {\text{Mn}}^{2 +} + 8 {\text{H}}_{2} \text{O}

{\text{MnO}}_{4}^{-} ⇒ \text{x} = 2

{\text{C}}_{2} {\text{O}}_{4}^{2 -} ⇒ \text{y} = 5

{\text{H}}^{+} ⇒ \text{z} = 1 6

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