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Excess of KI reacts with CuSO ₄ solution and then Na ₂ ~S ₂ O ₃ solution is added to it. Which of the statements is incorrect for this reaction?

Options

  1. ACu ₂ I ₂ is reduced
  2. BEvolved I ₂ is reduced
  3. CNa ₂ ~S ₂ O ₃ is oxidized
  4. DCul ₂ is formed

Correct answer

D. Cul ₂ is formed

Step-by-step solution

2 CuSO ₄+4 KI (excess) 2 ~K ₂ SO ₄+ Cu ₂ I ₂+ I ₂ Na ₂ ~S ₂ O ₃+ I ₂ Na ₂ ~S ₄ O ₆+2 Nal

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