The magnetic behaviour of Li 2 O , Na 2 O 2 and KO 2 , respectively, are

Step-by-step solution

In the structure Li 2 O each lithium atom loses one electron to form 2 cations Li + and oxygen atom gains two electrons to form the anion O 2 - . It has no unpaired electrons. So, it is diamagnetic in nature. The peroxide O 2 2 - present in Na 2 O 2 has 4 electron in π * 2 p , thus all are paired. So, it is diamagnetic in nature. In the structure KO 2 oxygen is present in O 2 - . The number of electrons present is 17, where the where the sixteen electrons are from two oxygen atoms and one from the negative cha