Match List I with List II List I List II A. Cobalt catalyst I. ( H...

Hydrogen reacts with carbon monoxide in presence of cobalt catalyst to give methanol.

$2{H}_{2}\left(g\right) + CO\left(g\right)\overset{\text{Cobalt catalyst}}{\to}{CH}_{3}OH\left(l\right)$

As the mixture of $CO$ and ${H}_{2}$ is used for the synthesis of methanol and a number of hydrocarbons, it is called synthesis gas or syngas. The process of producing syngas from coal is called coal gasification.

$C\left(s\right) + {H}_{2}O\left(g\right)\overset{1270K}{\to}CO\left(g\right) + {H}_{2}\left(g\right)$

The reaction of steam with hydrocarbons or coke at high temperature in presence of nickel catalyst gives a mixture of $CO$ and ${H}_{2}$, called water gas.

${CH}_{4}\left(g\right) + {H}_{2}O\left(g\right)\mathop{\to}_{Ni}^{1270K}CO\left(g\right) + 3{H}_{2}\left(g\right)$

Electrolysis of brine solution produces ${H}_{2}$ gas at cathode and ${Cl}_{2}$ gas at anode.

Cathode: $2{H}_{2}O\left(l\right) + 2{e}^{-} \to {H}_{2}\left(g\right) + 2{OH}^{-}\left(aq\right)$

Anode: $2{Cl}^{-} ( aq ) \to {Cl}_{2} ( g ) + 2{e}^{-}$

The overall reaction is $2{Na}^{+} ( aq ) + 2{Cl}^{-} ( aq ) + 2{H}_{2}O ( l ) \to {Cl}_{2} ( g ) + {H}_{2} ( g ) + 2{Na}^{+} ( aq ) + 2{OH}^{-} ( aq )$

So, the correct answer is A-IV, B-III, C-II, D-I