JEE Main202228 Jul 2022Morning ShiftChemistrys Block ElementsActual
Which of the following statements is incorrect?
Options
- ALow solubility of LiF in water is due to its small hydration enthalpy.
- BKO 2 is paramagnetic.
- CSolution of sodium in liquid ammonia is conducting in nature.
- DSodium metal has higher density than potassium metal
Correct answer
A. Low solubility of LiF in water is due to its small hydration enthalpy.
Step-by-step solution
Due to the small size of Li + ion and F - ions, the lattice energy of LiF is very high. LiF is covalent in nature. Therefore, LiF is insoluble in water. KO 2 has 1 unpaired electron in π ⋆ 2 p   Molecular   orbital of O 2 - . Therefore, it is Paramagnetic. Lithium has lesser atomic weight than sodium. So, lithium has lesser density than sodium. But in the case of ' K ' and ' Na ', d -orbitals present in Potassium, which increases the volume of ' K '. Solution of sodium i