Which of the following statement is incorrect?

Due to the small size of ${Li}^{+}$ ion and ${F}^{-}$ions, the lattice energy of $LiF$ is very high. $LiF$ is covalent in nature. Therefore, $LiF$ is insoluble in water.

${KO}_{2}$ has $1$ unpaired electron in ${\pi}^{⋆}2pMolecularorbital$ of ${O}_{2}^{-}$ . Therefore, it is Paramagnetic.

Lithium has lesser atomic weight than sodium. So, lithium has lesser density than sodium. But in the case of '$K$' and '$Na$', $d$-orbitals present in Potassium, which increases the volume of '$K$'.

Solution of sodium in liquid ammonia is conducting in nature, due to presence of free electron.