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The change in internal energy ( U ) for the reaction H ₂( ~g )+ Br ₂( ~g ) 2 HBr (l) when 2.0 moles each of Br ₂( ~g ) and H ₂( ~g ) react is ( H ₂( ~g )+ Br ₂( ~g ) 2 HBr ( ~g ) ; H _ reaction =-109 ~kJ ; H _ vap of HBr =213 ~kJ ~mol ⁻¹ )

Options

  1. A-644 ~kJ
  2. B644 kJ
  3. C-322 ~kJ
  4. D-106 ~kJ

Correct answer

D. -106 ~kJ

Step-by-step solution

No Solution (deleted)

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