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Olympiad workbook
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NSEC
Chapter
Thermodynamics (C)

Olympiad workbook · NSEC · Thermodynamics (C)

From the following data aligned & 2 CH_6 ~N_2( )+5 O_2(~g) arrow 2...

From the following data 2CH6 N2(ℓ)+5O2( g)→2 N2( g)+2CO2( g)+6H2O( g)(ΔHr0=−2606 kJ) and H2O(ℓ)→H2O( g)(ΔHv0=44 kJ mol−1)\begin{aligned} & 2 \mathrm{CH}_6 \mathrm{~N}_2(\ell)+5 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{~N}_2(\mathrm{~g})+2 \mathrm{CO}_2(\mathrm{~g})+6 \mathrm{H}_2 \mathrm{O}(\mathrm{~g})\left(\Delta \mathrm{H}_{\mathrm{r}}^0=-2606 \mathrm{~kJ}\right) \text { and } \\ & \mathrm{H}_2 \mathrm{O}(\ell) \rightarrow \mathrm{H}_2 \mathrm{O}(\mathrm{~g})\left(\Delta \mathrm{H}_{\mathrm{v}}^0=44 \mathrm{~kJ} \mathrm{~mol}^{-1}\right) \end{aligned} Heat of combustion of CH6 N2\mathrm{CH}_6 \mathrm{~N}_2 at 298 K can be calculated as

Options

  1. A−1567 kJ mol−1-1567 \mathrm{~kJ} \mathrm{~mol}^{-1}
  2. B−1435 kJ mol−1-1435 \mathrm{~kJ} \mathrm{~mol}^{-1}
  3. C−1171 kJ mol−1-1171 \mathrm{~kJ} \mathrm{~mol}^{-1}
  4. D−2342 kJ mol−1-2342 \mathrm{~kJ} \mathrm{~mol}^{-1}

Correct answer

B. −1435 kJ mol−1-1435 \mathrm{~kJ} \mathrm{~mol}^{-1}

Step-by-step solution

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