JEE Main 202624 JanuaryMorning Shift
- Exam
- JEE Main
- Year
- 2026
- Date
- 24 January
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Solutions
JEE Main 2026 · 24 January · Morning Shift · Chemistry · Solutions
A solution is prepared by dissolving 0.3 g of a non-volatile...
A solution is prepared by dissolving 0.3 g of a non-volatile non-electrolyte solute 'A' of molar mass and 0.9 g of a non-volatile non-electrolyte solute ' ' of molar mass in at . Osmotic pressure of the solution will be
[Given: ]
[Given: ]
Options
- A0.82 atm
- B2.46 atm
- C1.23 atm
- D1.47 atm
Correct answer
B. 2.46 atm
Step-by-step solution
Calculate osmotic pressure using where n is total moles of solute particles.
Moles of solute A: mol
Moles of solute B: mol
Total moles: mol
Volume of solution: 100 mL = 0.1 L
Temperature: 27°C = 300 K
Osmotic pressure: atm
Moles of solute A: mol
Moles of solute B: mol
Total moles: mol
Volume of solution: 100 mL = 0.1 L
Temperature: 27°C = 300 K
Osmotic pressure: atm