Sea water, which can be considered as a 6 molar (6 M) solution of NaCl , has a density of 2 ~g ~mL^ -1 . The concentration of dissolved oxygen (O_2) in sea water is 5.8 ppm. Then the concentration of dissolved oxygen

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Sea water is 6 Molar in NaCl , So 1000 ml of sea water contains 6 mol of NaCl.
mass of solution = Volume

\times

density

=1000 \times 2

mass of solution

=2000 \mathrm{~g}

\begin{aligned}<br />& \text{ ppm }=\frac{\text{ mass of } \mathrm{O}_2}{2000} \times 10^6 \\<br>& \text{ mass of } \mathrm{O}_2=5.8 \times 2 \times 10^{-3} \\<br>& \quad=1.16 \times 10^{-2} \mathrm{~g}<br />\end{aligned}

molality for

\mathrm{O}_2=\frac{1.16 \times 10^{-2} / 32}{(2000-6 \times 58.5)} \times 1000

\begin{aligned} & =\frac{1.16 \times 10}{32 \times 1649} \\ = & 0.000219 \\ = & 2.19 \times 10^{-4}\end{aligned}

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\Rightarrow 2

Sea water, which can be considered as a 6 molar (6 M) solution of...

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