JEE Main20253 Apr 2025Morning ShiftChemistrySolutionsActual
2 moles each of ethylene glycol and glucose are dissolved in 500 g of water. The boiling point of the resulting solution is : (Given : Ebullioscopic constant of water .=0.52 ~K ~kg ~mol ⁻¹ )
Options
- A379.2 K
- B377.3 K
- C375.3 K
- D277.3 K
Correct answer
B. 377.3 K
Step-by-step solution
aligned & T _ b = i ₁ ~m ₁ k _ b + i ₂ ~m ₂ k _ b & =1 2 0.5 0.52+ 1 2 0.5 0.52=4.16 & ( ~T _ b )_ solution =373.16+4.16=377.3 ~K . aligned