JEE Main 20252 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2025
- Date
- 2 April
- Shift
- Morning Shift
- Subject
- Chemistry
- Chapter
- Solutions
JEE Main 2025 · 2 April · Morning Shift · Chemistry · Solutions
A solution is made by mixing one mole of volatile liquid A with 3...
A solution is made by mixing one mole of volatile liquid with 3 moles of volatile liquid . The vapour pressure of pure A is 200 mm Hg and that of the solution is 500 mm Hg. The vapour pressure of pure and the least volatile component of the solution, respectively, are :
Options
- A(1400 \mathrm{~mm} \mathrm{Hg}, \mathrm{A})
- B(1400 \mathrm{~mm} \mathrm{Hg}, \mathrm{B})
- C(600 \mathrm{~mm} \mathrm{Hg}, \mathrm{B})
- D(600 \mathrm{~mm} \mathrm{Hg}, \mathrm{A})
Correct answer
D. (600 \mathrm{~mm} \mathrm{Hg}, \mathrm{A})
Step-by-step solution
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As (\mathrm{P}_{\mathrm{A}}^{\mathrm{o}} \lt \mathrm{P}_{\mathrm{B}}^{\mathrm{o}} \Rightarrow \mathrm{A}) is least volatile.$
As (\mathrm{P}_{\mathrm{A}}^{\mathrm{o}} \lt \mathrm{P}_{\mathrm{B}}^{\mathrm{o}} \Rightarrow \mathrm{A}) is least volatile.$