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JEE Main 202528 JanuaryEvening Shift
Exam
JEE Main
Year
2025
Date
28 January
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2025 · 28 January · Evening Shift · Chemistry · Solutions

Assume a living cell with 0.9 \%(ω / ω) of glucose solution...

Assume a living cell with 0.9%(ω/ω)0.9 \%(\omega / \omega) of glucose solution (aqueous). This cell is immersed in another solution having equal mole fraction of glucose and water. (Consider the data upto first decimal place only) The cell will :

Options

  1. Ashow no change in volume since solution is 0.9%(ω/ω)0.9 \%(\omega / \omega)
  2. Bshrink since solution is 0.5%(ω/ω)0.5 \%(\omega / \omega)
  3. Cswell up since solution is 1%(ω/ω)1 \%(\omega / \omega)
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

Living cell =0.9gm=0.9 \mathrm{gm} in 100 gm of solution %w/w=0.9\% \mathrm{w} / \mathrm{w}=0.9 Solution is have equal moles of glucose and water =0.5=0.5 Weight of solution =0.5×180+0.5×18=99gm=0.5 \times 180+0.5 \times 18=99 \mathrm{gm} %w/w≃90%\% \mathrm{w} / \mathrm{w} \simeq 90 \% Concentrated solution = Cell will shrink.
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