JEE Main202523 Jan 2025Evening ShiftChemistrySolutionsActual
Consider a binary solution of two volatile liquid components 1 and 2 . x₁ and y₁ are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of 1 x₁ vs 1 y₁ are given respectively as:
Options
- AP ₂^0 P ₁^0 , P ₂^0- P ₁^0 P ₂^0
- BP ₁^0 P ₂^0 , P ₂^0- P ₁^0 P ₂^0
- CP ₁^0 P ₂^0 , P ₁^0- P ₂^0 P ₂^0
- DP ₂^0 P ₁^0 , P ₁^0- P ₂^0 P ₂^0
Correct answer
B. P ₁^0 P ₂^0 , P ₂^0- P ₁^0 P ₂^0
Step-by-step solution
Given mole fraction of liquid 1 in liquid and vapour phase is x₁ and y₁ respectively. aligned & P ₁= P _ T y₁= P ₁^0 x₁ & P _ T x₁ = P ₁^0 y₁ & P ₂^0+x₁ ( P ₁^0+ P ₂^0 ) x₁ = P ₁^0 y₁ & P ₂^0 x₁ + ( P ₁^0+ P ₂^0 )= P ₁^0 y₁ & P ₂^0 x₁ = P ₁^0 y₁ - ( P ₁^0+ P ₂^0 ) & 1 x₁ = 1 y₂ ( P ₁^0 P ₂^0 )- ( P ₁^0+ P ₂^0 ) P ₂^0 aligned aligned & 1 x₁ = 1 y₂ ( P₁^0 P₂^0 )+ (P₂^0-P₁^0 ) P₂^0 & y=m x+c & Slope = P₁^0 P₂^0 ; Intercept = P₂^0-P₁^0 P₂^0 aligned