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Molality of 0 . 8 M H 2 SO 4 solution (density 1 . 06 g cm - 3 ) is _______ × 10 - 3 m . Round off your answer to the nearest integer.

Correct answer

0

Step-by-step solution

1000 ml solution contains 0 . 8 mol of H 2 SO 4 Mass of solution = 100 cm 3 × 1 . 06 g cm 3 = 1060 g Mass of solute (H 2 SO 4 ) = 0 . 8 × 98 = 78 . 4 g Mass of solvent = 1060 - 78 . 4 = 981 . 6 g Molality = moles of H 2 SO 4 mass of solvent ( in kg ) = 0 . 8 981 . 6 × 10 − 3 = 0 . 815 m = 815 × 10 - 3 m

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