The osmotic pressure of a dilute solution is 7 × 10 ^ 5 Pa at 273K...

Osmotic pressure can be calculated as,

$\pi = CRT$

π is the osmotic pressure

C is the molar concentration of the solute in the solution

R is the universal gas constant

Here given,

 ${T}_{1} = 273K{T}_{2} = 283K$ 

${\pi}_{1} = {CRT}_{1}\text{By putting the values in this equation, we get,}7 \times {10}^{5} = C \times R \times 273CR = \dfrac{7 \times {10}^{5}}{273}{\pi}_{2} = {CRT}_{2} = \dfrac{7 \times {10}^{5}}{273} \times 283 = 72 . 56 \times {10}^{4}{Nm}^{- 2}$