JEE Main202429 Jan 2024Morning ShiftChemistrySolutionsActual
The osmotic pressure of a dilute solution is 7 × 10 5 Pa at 273 K . Osmotic pressure of the same solution at 283 K is _ _ _ _ _ _ _ × 10 4 Nm - 2 .(Nearest integer)
Correct answer
0
Step-by-step solution
Osmotic pressure can be calculated as, π = CRT π is the osmotic pressure C is the molar concentration of the solute in the solution R is the universal gas constant Here given, T 1 = 273 K T 2 = 283 K π 1 = CRT 1 By putting the values in this equation, we get, 7 × 10 5 = C × R × 273 CR = 7 × 10 5 273 π 2 = CRT 2 = 7 × 10 5 273 × 283 = 72 . 56 × 10 4 Nm − 2