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JEE Main 202427 JanuaryMorning Shift
Exam
JEE Main
Year
2024
Date
27 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2024 · 27 January · Morning Shift · Chemistry · Solutions

A solution of two miscible liquids showing negative deviation from...

A solution of two miscible liquids showing negative deviation from Raoult's law will have :

Options

  1. Aincreased vapour pressure, increased boiling point
  2. Bincreased vapour pressure, decreased boiling point
  3. Cdecreased vapour pressure, decreased boiling point
  4. Ddecreased vapour pressure, increased boiling point

Correct answer

D. decreased vapour pressure, increased boiling point

Step-by-step solution

Raoult's law states that a solvent's partial vapour pressure in a solution (or mixture) is equal or identical to the vapour pressure of the pure solvent multiplied by its mole fraction in the solution.

The compounds which show negative deviation from Raoult's law are a mixture of acetone and chloroform. This results in the formation of the hydrogen bonding between atoms of molecules. There is a decrease in the vapour pressure of the mixture that results in a negative deviation from Raoult's law.

Solution with negative deviation has
PT<PA0XA+PB0XBPA<PA0XAPB<PB0XB{P}_{T} < {{P}_{A}}^{0}{X}_{A} + {{P}_{B}}^{0}{X}_{B}{P}_{A} < {{P}_{A}}^{0}{X}_{A}{P}_{B} < {{P}_{B}}^{0}{X}_{B}
 If vapour pressure decreases, so the boiling point increases.

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