An aqueous solution of volume 300 cm 3 contains 0 . 63 g of protein. The osmotic pressure of the solution at 300 K is 1 . 29 mbar . The molar mass of the protein is gmol - 1 . Given : R = 0 . 083 L bar K - 1 mol - 1

Step-by-step solution

The osmotic pressure of a non-electrolytic solution can be calculated as follows, π = CRT π   = osmotic pressure C = molarity = Number   of   moles Volume   of   solution   in   L 1 . 29 × 10 - 3 = 0 . 63 ( MW ) ( 0 . 3 ) × ( 0 . 083 ) × 300 MW = 0 . 63 × 0 . 083 × 300 ( 0 . 3 ) × 1 . 29 × 10 - 3 =   40534 . 88 ≈ 40535 (Nearest integer)