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JEE Main 202310 AprilEvening Shift
Exam
JEE Main
Year
2023
Date
10 April
Shift
Evening Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2023 · 10 April · Evening Shift · Chemistry · Solutions

An aqueous solution of volume 300 cm ^ 3 contains 0 . 63g of...

An aqueous solution of volume 300cm3300{cm}^{3} contains 0.63g0 . 63g of protein. The osmotic pressure of the solution at 300K300K is 1.29mbar1 . 29mbar. The molar mass of the protein is gmol−1{gmol}^{- 1}.

Given : R=0.083LbarK−1mol−1R = 0 . 083{L}_{bar}{K}^{- 1}{mol}^{- 1}

Correct answer

0

Step-by-step solution

The osmotic pressure of a non-electrolytic solution can be calculated as follows,

π=CRT\pi = CRT

π\pi= osmotic pressure

CC = molarity=NumberofmolesVolumeofsolutioninL= \dfrac{Numberofmoles}{VolumeofsolutioninL}

\left(1 . 29 \times {10}^{- 3}\right) = \dfrac{0 . 63}{( MW ) ( 0 . 3 )} \times ( 0 . 083 ) \times 300</p><p></p><p>MW = \dfrac{0 . 63 \times 0 . 083 \times 300}{( 0 . 3 ) \times \left(1 . 29 \times {10}^{- 3}\right)}</p><p></p><p>= 40534 . 88</p><p></p><p>\approx 40535$ (Nearest integer)

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