If the boiling points of two solvents X and Y (having same molecular weights) are in the ratio 2: 1 and their enthalpy of vaporizations are in the ratio 1 : 2 , then the boiling point elevation constant of X is m times the boiling point elevation constant of Y . The value of m is (nearest integer).

Step-by-step solution

The boiling point elevation constant K b of a volatile liquid is given by the following expression K b = RT b 2 M ΔH v Where T b = boiling point of the liquid M = molar mass of the liquid ΔH v = Enthalpy of vaporisation The boiling points of the two solvents are in the ratio 2 : 1 , which means that the boiling point elevation constants are also in the ratio 2 : 1 . Let's call the boiling point elevation constant of solvent X as ( T b ) x , and the boiling point elevation constant of solvent Y