At 27 ° C , a solution containing 2 . 5g of solute in 250 . 0mL of...

The osmotic pressure of a non-electrolytic solution can be calculated as follows,

$\pi = CRT$

$\pi$= osmotic pressure

$C$ = molarity

$\dfrac{400Pa}{{10}^{5}} = \dfrac{\dfrac{2 . 5g}{{M}_{o}}}{250 / 1000L} \times 0 . 83\dfrac{L - bar}{K . mol} \times 300K$

$⇒ \dfrac{400 \times {10}^{- 5}}{( 1 . 01325 )} = \left[\dfrac{2 . 5 \times 1000}{{M}_{o} \times 250}\right]0 . 083 \times 300$

$⇒ 400 \times {10}^{- 5} = \dfrac{10}{{M}_{o}} \times 0 . 083 \times 300$

$⇒ {M}_{o} = \dfrac{10 \times 0 . 83 \times 300}{400} \times {10}^{5}$

$⇒ {M}_{o} = \left[\dfrac{10 \times 0 . 083 \times 3}{4}\right] \times {10}^{5}$

$⇒ {M}_{o} = 62250$ gram/mole