Some amount of dichloromethane CH 2 Cl 2 is added to 671 . 141 mL of chloroform CHCl 3 to prepare 2 . 6 × 10 - 3 M solution of CH 2 Cl 2 DCM . The concentration of DCM is _____ ppm (by mass). Given: Atomic mass : C = 12 ; H : 1 ; Cl = 35 . 5 density of CHCl 3 = 1 . 49 g cm - 3

Step-by-step solution

Molarity =   mole     Volume   in   L   = mass / Molar   mass Volume   in   L 2 . 6 × 10 - 3 = x / 85 0 . 67141 x = 0 . 148   g The number of ppm = mass   of   solute mass   of   solution × 10 6 Mass of solution = density of solution × Volume of solution DCM in ppm = 0 . 148 1 . 49 × 671 . 141 × 10 6 = 148 ppm .