' x ' g of molecular oxygen ( O _ 2 ) is mixed with 200g of neon...

Given

${O}_{2} + Ne$

Xgm200gm$</p><p>${P}_{total} = 25$bar;${P}_{Ne} = 20$</p><p>According to Dalton's law of partial pressure.</p><p>${P}_{{O}_{2}} + {P}_{Ne} = 25$</p><p>${P}_{{O}_{2}} = 25 - 20 = 5$bar</p><p>Also,${P}_{{O}_{2}} = {X}_{{O}_{2}}{P}_{T}Where{X}_{{O}_{2}} = molefractionofoxygengas .$</p><p>$5 = \dfrac{\dfrac{x}{32}}{\dfrac{x}{32} + \dfrac{200}{20}} \times 25$</p><p>$5x = x + 320$</p><p>$4x = 320$</p><p>$x = \dfrac{320}{4} = 80gm