The molarity of the solution prepared by dissolving $6 . 3g$ of oxalic acid \left({H}_{2}{C}_{2}{O}_{4} \cdot 2{H}_{2}O\right) in 250mL $of water in$ mol{L}^{- 1} is $x \times {10}^{- 2} .$ The value of $x$ is _________ . (Nearest integer)
[Atomic mass : $H: 1 . 0, C: 12 . 0, 0: 16 . 0J$ ]

Question

The molarity of the solution prepared by dissolving

6 . 3g

of oxalic acid \left({H}_{2}{C}_{2}{O}_{4} \cdot 2{H}_{2}O\right) in 250mL

of water in

mol{L}^{- 1} is

x \times {10}^{- 2} .

The value of

x

is _________ . (Nearest integer)
[Atomic mass :

H: 1 . 0, C: 12 . 0, 0: 16 . 0J

]

Quantrex Academy · Accepted Answer

Correct answer: 0

M = W _ solute × 1000 GMM _ solute × V _ ml = (6 . 3 × 1000)/(126 × 250) = 0 . 2M = 20 × 10 ^ - 2 So X = 20

The molarity of the solution prepared by dissolving 6 . 3g of...