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JEE Main 202122 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
22 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2021 · 22 July · Morning Shift · Chemistry · Solutions

If the concentration of glucose ( C _ 6 H _ 12 O _ 6 ) in blood is...

If the concentration of glucose (C6H12O6)\left({C}_{6}{H}_{12}{O}_{6}\right) in blood is 0.72gL−1,0 . 72g{L}^{- 1}, the molarity of glucose in blood is −×10−3M- \times {10}^{- 3}M (Nearest integer):
[[Given : Atomic mass of C=12,H=1,O=16u]C = 12, H = 1, O = 16u ]

Correct answer

0

Step-by-step solution

[Glucose]=C(gm/ℓ)M(gm/mol)=0.72180=4×10−3M\left[Glucose\right] = \dfrac{C ( gm / ℓ )}{M ( gm / mol )} = \dfrac{0 . 72}{180} = 4 \times {10}^{- 3}M
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