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If the concentration of glucose C 6 H 12 O 6 in blood is 0 . 72 g L - 1 , the molarity of glucose in blood is - × 10 - 3 M (Nearest integer): [ Given : Atomic mass of C = 12 , H = 1 , O = 16 u ]

Correct answer

0

Step-by-step solution

Glucose = C ( gm / ℓ ) M ( gm / mol ) = 0 . 72 180 = 4 × 10 - 3 M

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