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JEE Main 202120 JulyMorning Shift
Exam
JEE Main
Year
2021
Date
20 July
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2021 · 20 July · Morning Shift · Chemistry · Solutions

At 20 ° C , the vapour pressure of benzene is 70 torr and that of...

At 20°C20 ° C, the vapour pressure of benzene is 7070 torr and that of methyl benzene is 2020 torr. The mole fraction of benzene in the vapour phase at 20°C20 ° C above an equimolar mixture of benzene and methyl benzene is __ \times {10}^{- 2} . (Nearest integer)

Correct answer

0

Step-by-step solution

PB∘=70PT∘=20XB=0.5=XT{P}_{B}^{∘} = 70{P}_{T}^{∘} = 20{X}_{B} = 0.5 = {X}_{T}

Now yB=XBPB∘XBPBo+XTPT∘{y}_{B} = \dfrac{{X}_{B}{P}_{B}^{∘}}{{X}_{B}{P}_{B}^{o} + {X}_{T}{P}_{T}^{∘}}

=70×0.570×0.5+20×0.5=78×10−2= \dfrac{70 \times 0.5}{70 \times 0.5 + 20 \times 0.5} = 78 \times {10}^{- 2}

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