How much amount of NaCl should be added to 600g of water (ρ = 1.00g...

$∆ {T}_{f} = 0.2 ° C$
$∆ {T}_{f} =$ $i{k}_{f}m$
$0.2 = 2 \times 2 \times \dfrac{\omega}{58.5} \times \dfrac{1000}{600}$
$\omega = \dfrac{0.2 \times 58.5 \times 600}{1000 \times 4} = \dfrac{1.2 \times 58.5}{40} = 01.76g$

Freezing point depression is the phenomena that describes why adding a solute to a solvent results in the lowering of the freezing point of the solvent.