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JEE Main 20207 JanuaryMorning Shift
Exam
JEE Main
Year
2020
Date
7 January
Shift
Morning Shift
Subject
Chemistry
Chapter
Solutions

JEE Main 2020 · 7 January · Morning Shift · Chemistry · Solutions

At 35 ^ o C, the vapour pressure of C S _ 2 , is 512mm Hg and that...

At 35oC,35{}^{o}C, the vapour pressure of CS2,C{S}_{2}, is 512mm512mm Hg and that of acetone is 144mmHg.144mmHg . A solution of CS2C{S}_{2} in acetone has a total vapour pressure of 600mmHg600mmHg . The false statement amongst the following is:

Options

  1. ARaoult's law is not obeyed by this system
  2. Ba mixture of 100mLCS2100mL{CS}_{2} and 100mL100mL acetone has a volume <200mL< 200mL
  3. CCS2{CS}_{2} and acetone are less attracted to each other than to themselves
  4. Dheat must be absorbed in order to produce the solution at 35oC{35}^{o}C

Correct answer

B. a mixture of 100mLCS2100mL{CS}_{2} and 100mL100mL acetone has a volume <200mL< 200mL

Step-by-step solution

Pobserved=600{\text{P}}_{\text{observed}} = 600

PCal=PA0xA+PB0xB{\text{P}}_{\text{Cal}} = {\text{P}}_{\text{A}}^{\text{0}} {\text{x}}_{\text{A}} {\text{+P}}_{\text{B}}^{\text{0}} {\text{x}}_{\text{B}}

=512x+344−344x= 512\text{x} + 344 - 344\text{x}

=168x+344= 168\text{x} + 344

=512= 512 (If x=1\text{x} = 1 for maximum value)

Thus, Pcal<Pobserved{\text{P}}_{\text{cal}} < {\text{P}}_{\text{observed}}

Thus' the process is deviated from Raoult's law, showing positive deviation from Raoult's law.

ΔH>0,\Delta H > 0, i.e., is absorbed
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