A solution is prepared by dissolving 0.6 g of urea (molar mass =...

$i$ factor of glucose and urea are 1 : 1 respectively.

Moles of glucose $= \dfrac{weight}{Molecular wieght} = \dfrac{1.8}{180} = {10}^{- 2}$

Moles of urea $= \dfrac{0.6}{60} = {10}^{- 2}$

Total mole of solute $= {10}^{- 2} + {10}^{- 2} = 2 \times {10}^{- 2}$

Concentration of solution $= \dfrac{2 \times {10}^{- 2}}{100 \times {10}^{- 3}} = 0.2$

Osmotic pressure $( \pi ) = CRT$

$= 0.2 \times 0.0821 \times 300 = 4.926atm$