A solution is prepared by dissolving 0.6 g of urea (molar mass = 60 g m o l - 1 ) and 1.8 g of glucose (molar mass = 180 g m o l - 1 ) in 100 mL of water at 27 o C . The osmotic pressure of the solution is: ( R = 0.08206 L atm K - 1 m o l - 1 )

Step-by-step solution

i factor of glucose and urea are 1 : 1 respectively. Moles of glucose = weight Molecular wieght = 1.8 180 = 10 - 2 Moles of urea = 0.6 60 = 10 - 2 Total mole of solute = 10 - 2 + 10 - 2 = 2 × 10 - 2 Concentration of solution = 2 × 10 - 2 100 × 10 - 3 = 0.2 Osmotic pressure ( π ) = C R T = 0.2 × 0.0821 × 300 = 4.926   a t m