JEE Main2016ChemistrySolutionsActual
The solubility of N 2 in water at 300   K and 500   torr partial pressure is 0 .01 g L − 1 . The solubility (in g L − 1 ) at 750   torr partial pressure is:
Options
- A0.0075
- B0.005
- C0 . 02
- D0.015
Correct answer
D. 0.015
Step-by-step solution
p   =  K H   X where p → Partial pressure of gas X 2 → Mole fraction of gas in solution K H  = Henry's law constant So, p ∝ solubility p 1 p 2  =   s 1 s 2   ⇒   500 0 . 01  =   750 x ∴   x  =  0 . 015   g / L