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18 g glucose C 6 H 12 O 6 is added to 178 . 2 g water. The vapour pressure of water (in torr) for this aqueous solution is:

Options

  1. A752 . 4
  2. B759 . 0
  3. C7 . 6
  4. D76 . 0

Correct answer

A. 752 . 4

Step-by-step solution

∆ P P o = Mole fraction of glucose. 760 - P S o l n 760 = W 1 M w t 1 W 1 M . w t 1 + w 2 M . w t 2   = 18 180 18 180 + 178.2 18 = 0.1 0.1 + 9.9 = 1 100 760 - P S o l n = 760 100 P S o l = 752.4

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