JEE Main2012ChemistrySolutionsActual
The freezing point of a 1.00 ~m aqueous solution of HF is found to be -1.91^ C . The freezing point constant of water, K_f is 1.86 ~K ~kg ~mol ⁻¹ . The percentage dissociation of HF at this concentration is
Options
- A30 %
- B10 %
- C5.2 %
- D2.7 %
Correct answer
D. 2.7 %
Step-by-step solution
T_ f =K_ f m i aligned & i= T_ f K_ f m = 1.91 1.86 1 =1.02 & For HI H ⁺+ I ⁻ & (1- ) & 1- + + =i=1.027 & 1+ =1.027 & =0.027 or 2.7 % aligned