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If 10⁻⁴ dm ^3 of water is introduced into a 1.0 dm ^3 flask to 300 ~K , how many moles of water are in the vapour phase when equilibrium is established? (Given : Vapour pressure of H ₂ O at 300 ~K is 3170 ~Pa ; R =8.314 ~J ~K ⁻¹ ~mol ⁻¹ )

Options

  1. A5.56 10⁻³ ~mol
  2. B1.53 10⁻² ~mol
  3. C4.46 10⁻² ~mol
  4. D1.27 10⁻³ ~mol

Correct answer

D. 1.27 10⁻³ ~mol

Step-by-step solution

n = PV RT ==128 10⁻⁵ moles = 3170 10⁻⁵ ~atm 1 ~L 0.0821 ~L ~atm k ^ - 1 mol ^ - 1 3 0 0 K 1.27 10⁻³ ~mol

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