Two liquids X and Y form an ideal solution. At 300 ~K , vapour pressure of the solution containing 1 mol of X and 3 ~mol of Y is 550 ~mm Hg . At the same temperature, if 1 ~mol of Y is further added to this solution, vapour pressure of the solution increases by 10 ~mm Hg . Vapour pressure (in mmHg ) of X and Y in their pure states will be, respectively :

Step-by-step solution

aligned & P_T=P_X^0 x_X+P_Y^0 x_Y & x_X= mol fraction of X & x_Y= mol fraction of Y & 550=P_x^ ( 1 1+3 )+P_Y^ ( 3 1+3 ) & = P_X^0 4 + 3 P_Y^0 4 & 550(4)=P_X^0+3 P_Y^0 aligned Further 1 ~mol of Y is added and total pressure increases by 10 ~mm Hg . aligned & 550+10= P _X^ ( 1 1+4 )+ P _Y^ ( 4 1+4 ) & 560(5)= P _ X ^ +4 P _Y^ (2) aligned By solving (1) and (2) We get, P _ x ^ =400 ~mm Hg P_Y^ =600 ~mm Hg