JEE Main2002ChemistrySolutionsActual
Freezing point of an aqueous solution is (-0.186)^ C . Elevation of boiling point of the same solution is K _ b =0.512^ C , K _ f =1.86^ C , find the increase in boiling point.
Options
- A0.186 ^ C
- B0.0512 ^ C
- C0.092 ^ C
- D0.2372 ^ C
Correct answer
B. 0.0512 ^ C
Step-by-step solution
T _ b = K _ b W _ B M _ B W _ A 1000 ; T _ f = K _ f W _ B M _ B W _ A 1000 ; T _ b T _ f = K _ b K _ f = T _ b -0.186 = 0.512 1.86 =0.0512^0 C