Consider two radiations of wavelengths
1. $\lambda_1 = 2000$ Å
2. $\lambda_2 = 6000$ Å
The ratio of the energies of these two radiations $\left(\dfrac{E_1}{E_2}\right)$ is ________ (Nearest integer).

Question

Consider two radiations of wavelengths 1. λ_1 = 2000 Å 2. λ_2 = 6000 Å The ratio of the energies of these two radiations ((E_1)/(E_2)) is ________ (Nearest integer).

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Correct answer: 0

The energy of a photon is given by the relation:

E = \dfrac{hc}{\lambda}

For the two radiations, the energies are

E_1 = \dfrac{hc}{\lambda_1}

and

E_2 = \dfrac{hc}{\lambda_2}

.

The ratio of their energies is:

\dfrac{E_1}{E_2} = \dfrac{\lambda_2}{\lambda_1}

Substituting the given values

\lambda_1 = 2000

and

\lambda_2 = 6000

:

\dfrac{E_1}{E_2} = \dfrac{6000}{2000} = 3

Answer:

3

Consider two radiations of wavelengths 1. λ_1 = 2000 Å 2. λ_2 =...

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