Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.
A. $n = 3, l = 2, m = +1$
B. $n = 4, l = 0, m = 0$
C. $n = 6, l = 1, m = 0$
D. $n = 5, l = 1, m = +1$
E. $n = 2, l = 1, m = +1$
Choose the correct answer from the options given below:

Question

Arrange the following atomic orbitals of multi electron atoms in order of increasing energy.
A.

n = 3, l = 2, m = +1

B.

n = 4, l = 0, m = 0

C.

n = 6, l = 1, m = 0

D.

n = 5, l = 1, m = +1

E.

n = 2, l = 1, m = +1

Choose the correct answer from the options given below:

Quantrex Academy · Accepted Answer

Correct answer: D. E < B < A < D < C

The energy of an atomic orbital in a multi-electron atom is determined by the

(n + l)

rule. Orbitals with a lower value of

(n + l)

have lower energy. If two orbitals have the same

(n + l)

value, the one with the lower

n

value has lower energy.

Calculating the

(n + l)

value for each given orbital:
A.

n = 3, l = 2 \Rightarrow n + l = 5

B.

n = 4, l = 0 \Rightarrow n + l = 4

C.

n = 6, l = 1 \Rightarrow n + l = 7

D.

n = 5, l = 1 \Rightarrow n + l = 6

E.

n = 2, l = 1 \Rightarrow n + l = 3

Arranging the orbitals in increasing order of their

(n + l)

values, we get:

3 < 4 < 5 < 6 < 7

This corresponds to the order:

E < B < A < D < C

Answer:

E < B < A < D < C

Arrange the following atomic orbitals of multi electron atoms in...