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JEE Main 20266 AprilMorning Shift
Exam
JEE Main
Year
2026
Date
6 April
Shift
Morning Shift
Subject
Chemistry
Chapter
Structure of Atom

JEE Main 2026 · 6 April · Morning Shift · Chemistry · Structure of Atom

Match the LIST-I with LIST-II List-I Orbital List-II Radial nodes...

Match the LIST-I with LIST-II
List-I
Orbital
List-II
Radial nodes and nodal plane
A. 2s2sI. 11 Radial node + two nodal planes
B. 3s3sII. 11 Radial node + one nodal plane
C. 3p3pIII. 22 Radial nodes + No nodal plane
D. 4d4dIV. 11 Radial node + No nodal plane

Choose the correct answer from the options given below:

Options

  1. AA-IV, B-I, C-III, D-II
  2. BA-IV, B-II, C-III, D-I
  3. CA-III, B-I, C-IV, D-II
  4. DA-IV, B-III, C-II, D-I

Correct answer

D. A-IV, B-III, C-II, D-I

Step-by-step solution

The number of radial nodes is given by the formula n−l−1n - l - 1.

The number of nodal planes (angular nodes) is given by ll.

For 2s2s orbital: n=2n = 2, l=0l = 0.
Radial nodes = 2−0−1=12 - 0 - 1 = 1.
Nodal planes = 00.
This matches A with IV.

For 3s3s orbital: n=3n = 3, l=0l = 0.
Radial nodes = 3−0−1=23 - 0 - 1 = 2.
Nodal planes = 00.
This matches B with III.

For 3p3p orbital: n=3n = 3, l=1l = 1.
Radial nodes = 3−1−1=13 - 1 - 1 = 1.
Nodal planes = 11.
This matches C with II.

For 4d4d orbital: n=4n = 4, l=2l = 2.
Radial nodes = 4−2−1=14 - 2 - 1 = 1.
Nodal planes = 22.
This matches D with I.

The correct matching is A-IV, B-III, C-II, D-I.

Answer: A-IV, B-III, C-II, D-I
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