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Match List - I with List - II . List- I (Colloid Preparation Method) List- II (Chemical Reaction) ( a ) Hydrolysis ( i ) 2 AuCl 3 + 3 HCHO + 3 H 2 O → 2 Au ( sol ) + 3 HCOOH + 6 HCl ( b ) Reduction ( ii ) As 2 O 3 + 3 H 2 S → As 2 S 3 ( sol ) + 3 H 2 O ( c ) Oxidation ( iii ) SO 2 + 2 H 2 S → 3 S ( sol ) + 2 H 2 O ( d ) Double Decomposition ( iv ) FeCl 3 + 3 H 2 O → Fe ( OH ) 3 ( sol ) + 3 HCl

Options

  1. A( a ) - ( i ) ,   ( b ) - ( iii ) ,   ( c ) - ( ii ) ,   ( d ) - ( iv )
  2. B( a ) - ( iv ) ,   ( b ) - ( i ) ,   ( c ) - ( iii ) ,   ( d ) - ( ii )
  3. C( a ) - ( i ) ,   ( b ) - ( ii ) ,   ( c ) - ( iv ) ,   ( d ) - ( iii )
  4. D( a ) - ( iv ) ,   ( b ) - ( ii ) ,   ( c ) - ( iii ) ,   ( d ) - ( i )

Correct answer

B. ( a ) - ( iv ) ,   ( b ) - ( i ) ,   ( c ) - ( iii ) ,   ( d ) - ( ii )

Step-by-step solution

Colloid preparation by Hydrolysis reaction: (no change in oxidation number.) FeCl 3 + 3 H 2 O → Fe ( OH ) 3 ( sol ) + 3 HCl Gold sol is prepared by reduction reaction: 2 AuCl 3 + 3 HCHO + 3 H 2 O → 2 Au ( sol ) + 3 HCOOH + 6 HCl Preparation of sulphur sol:(oxidation) SO 2 + 2 H 2   S → 3   S ( sol ) + 2 H 2 O Preparation of colloid by double decomposition reaction: As 2 O 3 + 3 H 2   S → As 2   S 3 ( sol ) + 3 H 2 O

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