Match List - I with List - II . List- I (Colloid Preparation Method) List- II (Chemical Reaction) ( a ) Hydrolysis ( i ) 2 AuCl _ 3 + 3HCHO + 3 H _ 2 O → 2Au ( sol ) + 3HCOOH + 6HCl ( b ) Reduction ( ii ) As _ 2 O _ 3 +

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Quantrex Academy · Accepted Answer

Correct answer: B. ( a ) - ( iv ) , ( b ) - ( i ) , ( c ) - ( iii ) , ( d ) - ( ii )

Colloid preparation by Hydrolysis reaction: (no change in oxidation number.)

${FeCl}_{3} + 3{H}_{2}O \to Fe ( OH{)}_{3} ( sol ) + 3HCl$

Gold sol is prepared by reduction reaction:

$2{AuCl}_{3} + 3HCHO + 3{H}_{2}O \to 2Au ( sol ) + 3HCOOH + 6HCl$

Preparation of sulphur sol:(oxidation)

${SO}_{2} + 2{H}_{2}S \to 3S ( sol ) + 2{H}_{2}O$

Preparation of colloid by double decomposition reaction:

${As}_{2}{O}_{3} + 3{H}_{2}S \to {As}_{2}{S}_{3} ( sol ) + 3{H}_{2}O$

List- $I$ (Colloid Preparation Method)		List- $II$ (Chemical Reaction)
$( a )$	Hydrolysis	$( i )$	$2{AuCl}_{3} + 3HCHO + 3{H}_{2}O \to 2Au ( sol ) + 3HCOOH + 6HCl$
$( b )$	Reduction	$( ii )$	${As}_{2}{O}_{3} + 3{H}_{2}S \to {As}_{2}{S}_{3} ( sol ) + 3{H}_{2}O$
$( c )$	Oxidation	$( iii )$	${SO}_{2} + 2{H}_{2}S \to 3S ( sol ) + 2{H}_{2}O$
$( d )$	Double Decomposition	$( iv )$	${FeCl}_{3} + 3{H}_{2}O \to Fe ( OH{)}_{3} ( sol ) + 3HCl$

Match List - I with List - II . List- I (Colloid Preparation...

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