For a linear plot of log ((x)/(m)) versus logp in a Freundlich...

According to Freundlich isotherm,

$\dfrac{x}{m} = k . {p}^{\dfrac{1}{n}}$ {Taking log}

$log \dfrac{x}{m} = log k + \dfrac{1}{n}log P$

$y = c + mx$ (Straight line equation)

So, intercept is $logk$ and slope is$= \dfrac{1}{\text{n}}$.