JEE Main20248 Apr 2024Morning ShiftMathematicsApplication of DerivativesActual

Let f(x)=4 ^3 x+3 3 ^2 x-10 . The number of points of local maxima of f in interval (0,2 ) is

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D. 2

Step-by-step solution

aligned & f ( x )=4 ^3( x )+3 3 ^2( x )-10 ; x (0,2 ) & f ^ ( x )=12 ^2 x [- ( x )]+3 3 (2 ( x ))[- ( x )] & f ^ ( x )=-6 ( x ) ( x )[2 ( x )+ 3 ] aligned local maxima at x = 5 6 , 7 6

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