JEE Main20248 Apr 2024Morning ShiftMathematicsApplication of DerivativesActual
The number of critical points of the function f(x)=(x-2)^ 2 / 3 (2 x+1) is
Options
- A1
- B2
- C0
- D3
Correct answer
B. 2
Step-by-step solution
aligned & f ( x )=( x -2)^ 2 / 3 (2 x +1) & f ^ ( x )= 2 3 ( x -2)^ -1 / 3 (2 x +1)+( x -2)^ 2 / 3 & f ^ ( x )=2 (2 x +1)+( x -2) 3( x -2)^ 1 / 3 & 3 x -1 ( x -2)^ 1 / 3 =0 aligned Critical points x = 1 3 and x =2