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JEE Main20205 Sep 2020Evening ShiftMathematicsApplication of DerivativesActual

Which of the following points lies on the tangent to the curve x 4 e y + 2 y + 1 = 3 at the point ( 1 , 0 ) ?

Options

  1. A( 2 ,   2 )
  2. B( 2 ,   6 )
  3. C( – 2 ,   6 )
  4. D( - 2 ,   4 )

Correct answer

C. ( – 2 ,   6 )

Step-by-step solution

e y y ' x 4 + 4 x 3 e y + 2 y ' 1 2 y + 1 = 0 at (1,0) y ' + 4 + y ' = 0    ⇒    y ' = - 2 equation of tangent at (1,0) is 2   x + y - 2 = 0 so option (3) is correct

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