JEE Main20248 Apr 2024Morning ShiftMathematicsArea Under CurvesActual
Let the area of the region enclosed by the curve y= x, x and the x axis between x=- to x= be A . Then A^2 is equal to ___________
Correct answer
0
Step-by-step solution
aligned & y= x, x & x- axis x- x= aligned aligned & ₀^ / 4 x=( x)_ / 4 ^0=1- 1 2 & _ - ^ -3 / 4 ( x- x)=(- x- x)_ - ^ -3 / 4 & =( x+ x)_ -3 / 4 ^ - & =(-1+0)- (- 1 2 - 1 2 ) & =-1+ 1 2 + 1 2 & _ / 4 ^ / 2 x d x=( x)_ / 4 ^ / 2 =1- 1 2 & A=4 & A^2=16 aligned