The area enclosed by y 2 = 8 x and y = 2 x that lies outside the triangle formed by y = 2 x , x = 1 , y = 2 2 , is equal to

Step-by-step solution

Intersection point of y 2 = 8 x   &   y = 2 x is 0 , 0   &   2 , 4 2   Area of ∆ A B C = 1 2 2 · 1 = 1 2 So required area = area between the curve y 2 = 8 x and the line y = 2 x - ar △ A B C = ∫ 0 4 8 x - 2 x d x - 1 2 = 32 2 3 - 8 2 - 1 2 = 13 2 6