Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Main202126 Aug 2021Evening ShiftMathematicsArea Under CurvesActual

Let a and b respectively be the points of local maximum and local minimum of the function f ( x ) = 2 x 3 - 3 x 2 - 12 x . If A is the total area of the region bounded by y = f ( x ) , the x -axis and the lines x = a and x = b , then 4 A is equal to ______.

Correct answer

0

Step-by-step solution

. f ' ( x ) = 6 x 2 - 6 x - 12 = 6 x 2 - x - 2 = 6 ( x - 2 ) ( x + 1 ) Clearly, f ' - 1 - > 0   &   f ' - 1 + < 0 Hence, x = - 1 is the point of local maximum. Also, f ' 2 - < 0   &   f ' 2 + > 0 Hence, x = 2 is the point of local minimum. ∴ a = - 1   &   b = 2 Points= 2 , - 20   &   - 1 , 7 A = ∫ - 1 0 2 x 3 - 3 x 2 - 12 x d x - ∫ 0 2 2 x 3 - 3 x 2 - 12 x d x = x 4 2 - x 3 - 6 x 2 - 1 0 - x 4 2 - x 3 - 6 x

Practice Area Under Curves on Quantrex Academy →

More from Area Under Curves

Passage: Consider the curve C₁ given by y = e^ -x for x [0, 10 ] , and the curve C₂ given by y = e^ -x ( x + x) for x [0, 10 ] . Let n be the total number of points of intersection 2026Passage: Consider the ellipses given by x^2 + 4y^2 = 1 and 4x^2 + y^2 = 1 . Question: If is the area of the common region that lies inside both the given ellipses, then the value o 2026The area of the region (x, y) : x^2 - 8x y -x is : 2026The area of the region (x, y) : 0 y 6 - x, y^2 4x - 3, x 0 is: 2026The area of the region R = (x, y): xy 27, 1 y x^2 is equal to: 2026The area of the region bounded by the curves x+3y^2=0 and x+4y^2=1 is equal to: 2026The area of the region (x, y): y - |x|, y |x x|, y 0 is: 2026If the area of the region bounded by 16x^2 - 9y^2 = 144 and 8x - 3y = 24 is A, then 3(A + 6 _e(3)) is equal to _______. 2026 Full Area Under Curves list All JEE Main PYQs