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JEE Main20206 Sep 2020Morning ShiftMathematicsArea Under CurvesActual

The area (in sq. units) of the region A = ( x , y ) : | x | + | y | ≤ 1 , 2 y 2 ≥ | x |

Options

  1. A1 3
  2. B7 6
  3. C1 6
  4. D5 6

Correct answer

D. 5 6

Step-by-step solution

Required area is, A = ar O A C + ar Δ A B C ⇒ A = 4 ∫ 0 1 / 2 2 y 2 d y + 1 2 · 1 2 · 1 2 ⇒ A = 4 2 3 y 3 0 1 / 2 + 1 8 = 5 6

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