JEE Main20206 Sep 2020Morning ShiftMathematicsArea Under CurvesActual
The area (in sq. units) of the region A = ( x , y ) : | x | + | y | ≤ 1 , 2 y 2 ≥ | x |
Options
- A1 3
- B7 6
- C1 6
- D5 6
Correct answer
D. 5 6
Step-by-step solution
Required area is, A = ar O A C + ar Δ A B C ⇒ A = 4 ∫ 0 1 / 2 2 y 2 d y + 1 2 · 1 2 · 1 2 ⇒ A = 4 2 3 y 3 0 1 / 2 + 1 8 = 5 6