JEE Main20198 Apr 2019Morning ShiftMathematicsArea Under CurvesActual
The area (in sq. units) of the region A = x , y ∈ R × R 0 ≤ x ≤ 3 , 0 ≤ y ≤ 4 , y ≤ x 2 + 3 x is
Options
- A26 3
- B8
- C53 6
- D59 6
Correct answer
D. 59 6
Step-by-step solution
The area of the region O C D is = ∫ 0 1 4 - x 2 + 3 x d x = 4 x - x 3 3 - 3 x 2 2 0 1 = 4 - 1 3 - 3 2 = 13 6 So, the area of the given region O A B C is = Area of O A B D - Area of O C D = 3 × 4 - 13 6 = 59 6