The area (in sq. units) of the region bounded by the curve x²=4 y and the straight line x=4 y-2 is :

Step-by-step solution

Let points of intersection of the curve and the line be P and Qx²=4 ( x+2 4 )x²-x-2=0x=2,-1 Point are (2,1) and (-1, 1 4 ) Area = _ -1 ² [ ( x+2 4 )- ( x² 4 ) ] d x= [ x² 8 + 1 2 x- x³ 12 ]_ -1 ²= ( 1 2 +1- 2 3 )- ( 1 8 - 1 2 + 1 12 )= 9 8