The area bounded by the curve y= (x) and the lines y=0, y= (3) and x=0 is equal to:

Step-by-step solution

To find the point of intersection of curves aligned & y= (x) and y= (3), put (x)= (3) & (x)- (3)=0 & (x)- (3)= (1) & x 3 =1, x=3 aligned aligned Required area & = ₀^3 (3) d x- ₁^3 (x) d x = & [x (3)]₀^3- [x (x)-x₁^3=2 . aligned