JEE Main 2021 · 26 August · Morning Shift · Mathematics · Binomial Theorem
A. 420×218420 \times {2}^{18}420×218
∑r=020r2(Cr20)=∑r(r⋅Cr20)=∑r=120r⋅20.Cr−119\mathop{∑}_{r = 0}^{20}{r}^{2}\left(Cr 20\right) = ∑ r\left(r \cdot Cr 20\right) = \mathop{∑}_{r = 1}^{20}r \cdot 20 . Cr - 1 19∑r=020r2(Cr20)=∑r(r⋅Cr20)=∑r=120r⋅20.Cr−119
⇒20∑r=120(r−1+1)⋅19Cr−1=20(∑r=120(r−1)⋅19Cr−1+∑r=120Cr−119)⇒ 20\mathop{∑}_{r = 1}^{20} ( r - 1 + 1) {\cdot}^{19}{C}_{r - 1} = 20\left(\mathop{∑}_{r = 1}^{20} ( r - 1 ) {\cdot}^{19}{C}_{r - 1} + \mathop{∑}_{r = 1}^{20} Cr - 1 19\right)⇒20∑r=120(r−1+1)⋅19Cr−1=20(∑r=120(r−1)⋅19Cr−1+∑r=120Cr−119)
⇒20(19∑r=220Cr−218+∑r=120Cr−119)⇒ 20\left(19\mathop{∑}_{r = 2}^{20} Cr - 2 18 + \mathop{∑}_{r = 1}^{20} Cr - 1 19\right)⇒20(19∑r=220Cr−218+∑r=120Cr−119)
⇒(380)218+20⋅219⇒220⋅(95+10)=(105)220=420×218⇒ ( 380 ) {2}^{18} + 20 \cdot {2}^{19} ⇒ {2}^{20} \cdot ( 95 + 10 ) = ( 105 ) {2}^{20} = 420 \times {2}^{18}⇒(380)218+20⋅219⇒220⋅(95+10)=(105)220=420×218